4SIN^4(X)+5=7COS^2(X)

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Solution for 4SIN^4(X)+5=7COS^2(X) equation: 


Simplifying
4SIN4(X) + 5 = 7COS2(X)

Multiply IN4S * X
4IN4SX + 5 = 7COS2(X)

Reorder the terms:
5 + 4IN4SX = 7COS2(X)

Multiply COS2 * X
5 + 4IN4SX = 7COS2X

Solving
5 + 4IN4SX = 7COS2X

Solving for variable 'I'.

Move all terms containing I to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 4IN4SX = -5 + 7COS2X

Combine like terms: 5 + -5 = 0
0 + 4IN4SX = -5 + 7COS2X
4IN4SX = -5 + 7COS2X

Divide each side by '4N4SX'.
I = -1.25N-4S-1X-1 + 1.75CN-4OS

Simplifying
I = -1.25N-4S-1X-1 + 1.75CN-4OS

Reorder the terms:
I = 1.75CN-4OS + -1.25N-4S-1X-1

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